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Answered by **Everest2017**

Let us say T= probability of head turning up = 1/2 in one tossH = probability of a tail turning up = 1/2 in one tossThen P (56 heads or more) = 1/2^100 [ C(100,56) + C(100,57) + C(100,58) + .... C(100,98) + C(100,99) + C(100,100) ] where C(N, R) = N ! / [ (N - R)! R! ] number of occurrances of R formed from N tosses.

Answered by **konrad509**

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