Author Annabartowitz in Mathematics, 07.13.2018

I only want to know how to install.  She wants 200 milliliters of 48% concentration solution. Cara has 60% and 40% concentration solutions in her lab. How many milliliters of 40% acid solution should be combined with 60% acid solution to make the required amount of 48% acid solution?  Okay so these are the two equations I had been trying. Where x=milliliters of 60% solution and y=milliliters of 40 percent solution X+Y=200 .6X+.4Y=200(.48) Thanks so much!!

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